What is the derivative of (x+1^3) ?

The derivative of (x+1^3) is 3(x+1)^2

What is the first derivative of (x+1^3) ?

The first derivative of (x+1^3) is 3(x+1)^2

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\frac{d}{d x} ((x + 1)^{3})

3 (x + 1)^{2}

Solution steps

\frac{d}{d x} ((x + 1)^{3})

Apply the chain rule:

3 (x + 1)^{2} \frac{d}{d x} (x + 1)

= 3 (x + 1)^{2} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 3 (x + 1)^{2} \cdot 1

Simplify

= 3 (x + 1)^{2}

\int_{0}^{1} \frac{61}{x ^{5}} d x

\int_{- 1}^{1} (3 x^{2} + 1)^{2} d x

\int \frac{- 4}{x ^{2}} d x

y = \frac{2 x - 3}{4 x + 1}

\frac{\partial}{\partial x} (3 (x - y) \cdot e^{3 y + 2 x^{2}})

What is the derivative of (x+1^3) ?
The derivative of (x+1^3) is 3(x+1)^2
What is the first derivative of (x+1^3) ?
The first derivative of (x+1^3) is 3(x+1)^2