What is the derivative of \sqrt[3]{x}*tan(x) ?

The derivative of \sqrt[3]{x}*tan(x) is (tan(x))/(3x^{2/3)}+\sqrt[3]{x}sec^2(x)

What is the first derivative of \sqrt[3]{x}*tan(x) ?

The first derivative of \sqrt[3]{x}*tan(x) is (tan(x))/(3x^{2/3)}+\sqrt[3]{x}sec^2(x)

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Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{1}{3 x ^{\frac{2}{3}}} tan (x) = \frac{tan ( x )}{3 x ^{\frac{2}{3}}}

f (x) = \frac{1}{3 + 2 x}, at x = 2

\int \frac{x ^{2}}{1 + x ^{4}} d x

\frac{d}{d x} (\frac{cos ( sin ( x + 1 ) )}{tan ( \frac{1}{x} )})

\int \frac{1}{1 - 9 x ^{2}} d x

\frac{d y}{d x} = e^{3 x + 2 y}

What is the derivative of \sqrt[3]{x}*tan(x) ?
The derivative of \sqrt[3]{x}*tan(x) is (tan(x))/(3x^{2/3)}+\sqrt[3]{x}sec^2(x)
What is the first derivative of \sqrt[3]{x}*tan(x) ?
The first derivative of \sqrt[3]{x}*tan(x) is (tan(x))/(3x^{2/3)}+\sqrt[3]{x}sec^2(x)