What is the derivative of y+xy ?

The derivative of y+xy is (dy)/(dx)+y+x(dy)/(dx)

What is the first derivative of y+xy ?

The first derivative of y+xy is (dy)/(dx)+y+x(dy)/(dx)

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\frac{d}{d x} (y + x y)

\frac{d y}{d x} + y + x \frac{d y}{d x}

Solution steps

\frac{d}{d x} (y + x y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d y}{d x} + \frac{d}{d x} (x y)

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

= \frac{d y}{d x} + y + x \frac{d y}{d x}

f (x) = 4 sec (x), at (\frac{π}{6})

f (x) = \frac{x - 1}{x + 1}

\frac{d y}{d x} = \frac{( x - 4 )}{y + 6}

f (x) = \frac{1}{( x + 3 ) ^{2}}

3 x^{2} - 5 x

What is the derivative of y+xy ?
The derivative of y+xy is (dy)/(dx)+y+x(dy)/(dx)
What is the first derivative of y+xy ?
The first derivative of y+xy is (dy)/(dx)+y+x(dy)/(dx)