What is area y=2,y=sec(x) ?

The answer to area y=2,y=sec(x) is (4pi)/3-ln(sqrt(3)+2)+ln(-sqrt(3)+2)

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area y=2,y=sec(x)

area

y = 2, y = sec (x)

\frac{4 π}{3} - ln (3 + 2) + ln (- 3 + 2)

Decimal Notation

1.55487 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{3}}^{\frac{π}{3}} ∣ 2 - sec (x) ∣ d x

Solve

\int_{- \frac{π}{3}}^{\frac{π}{3}} ∣ 2 - sec (x) ∣ d x : \frac{4 π}{3} - ln (3 + 2) + ln (- 3 + 2)

The area is:

= \frac{4 π}{3} - ln (3 + 2) + ln (- 3 + 2)

\frac{d}{d t} (sin^{2} (π t))

\frac{d}{d x} (\frac{1}{x ^{2} + y ^{2} + z ^{2}})

\frac{\partial}{\partial x} (x e^{x^{2} y})

\frac{- 40}{x ^{7}}

x \to 1 + lim (x^{\frac{1}{( 1 - x )}})

What is area y=2,y=sec(x) ?
The answer to area y=2,y=sec(x) is (4pi)/3-ln(sqrt(3)+2)+ln(-sqrt(3)+2)