What is the derivative of (-40)/(x^7) ?

The derivative of (-40)/(x^7) is (280)/(x^8)

What is the first derivative of (-40)/(x^7) ?

The first derivative of (-40)/(x^7) is (280)/(x^8)

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derivative of

\frac{- 40}{x ^{7}}

\frac{280}{x ^{8}}

Solution steps

\frac{d}{d x} (\frac{- 40}{x ^{7}})

Simplify

\frac{- 40}{x ^{7}} : - \frac{40}{x ^{7}}

= \frac{d}{d x} (- \frac{40}{x ^{7}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 40 \frac{d}{d x} (\frac{1}{x ^{7}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 40 \frac{d}{d x} (x^{- 7})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 40 (- 7 x^{- 7 - 1})

Simplify

- 40 (- 7 x^{- 7 - 1}) : \frac{280}{x ^{8}}

= \frac{280}{x ^{8}}

x \to 1 + lim (x^{\frac{1}{( 1 - x )}})

x \to - \infty lim (x^{2} e^{x})

f (x) = - 9 x^{2} + 1640 x - 37000

\frac{d}{d x} (- \frac{1}{x + 1})

\frac{d}{d s} (s L (y (s)))

What is the derivative of (-40)/(x^7) ?
The derivative of (-40)/(x^7) is (280)/(x^8)
What is the first derivative of (-40)/(x^7) ?
The first derivative of (-40)/(x^7) is (280)/(x^8)