What is the derivative of f(x)=x^2-x+1 ?

The derivative of f(x)=x^2-x+1 is 2x-1

What is the first derivative of f(x)=x^2-x+1 ?

The first derivative of f(x)=x^2-x+1 is 2x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{2} - x + 1

2 x - 1

Solution steps

\frac{d}{d x} (x^{2} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 2 x - 1 + 0

Simplify

= 2 x - 1

x \to 0 lim (x^{3})

\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

8 y^{^{''}} - 2 y^{^{'}} - y = 4 + 5 sin (2 t)

y = x^{2} - 3 x, y = 2 x + 6

f (x) = \frac{2 x}{e ^{x}}

What is the derivative of f(x)=x^2-x+1 ?
The derivative of f(x)=x^2-x+1 is 2x-1
What is the first derivative of f(x)=x^2-x+1 ?
The first derivative of f(x)=x^2-x+1 is 2x-1