What is the (e^{-(x^2)/2})^' ?

The (e^{-(x^2)/2})^' is -e^{-(x^2)/2}x

What is the first (e^{-(x^2)/2})^' ?

The first (e^{-(x^2)/2})^' is -e^{-(x^2)/2}x

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(e^{- \frac{x ^{2}}{2}})^{^{'}}

- e^{- \frac{x ^{2}}{2}} x

Solution steps

(e^{- \frac{x ^{2}}{2}})^{'}

Apply the chain rule:

e^{- \frac{x ^{2}}{2}} (- \frac{x ^{2}}{2})^{'}

= e^{- \frac{x ^{2}}{2}} (- \frac{x ^{2}}{2})^{'}

(- \frac{x ^{2}}{2})^{'} = - x

= e^{- \frac{x ^{2}}{2}} (- x)

Simplify

= - e^{- \frac{x ^{2}}{2}} x

\int \frac{7}{1 - x ^{2}} d x

\frac{\partial}{\partial x} (35 x^{6} y^{4} - 24 x^{5} y^{3})

\frac{d y}{d t} - \frac{3}{t} y = 2 t^{3} e^{2 t}

\frac{d}{d x} (x^{3} + 2 x^{2} - 4 x + 2)

k = 1 \sum \infty e^{- k}

What is the (e^{-(x^2)/2})^' ?
The (e^{-(x^2)/2})^' is -e^{-(x^2)/2}x
What is the first (e^{-(x^2)/2})^' ?
The first (e^{-(x^2)/2})^' is -e^{-(x^2)/2}x