What is the ((x+30)\sqrt[3]{2-x})^' ?

The ((x+30)\sqrt[3]{2-x})^' is cube root of 2-x}-(x+30)/(3(2-x)^{2/3)

What is the first ((x+30)\sqrt[3]{2-x})^' ?

The first ((x+30)\sqrt[3]{2-x})^' is cube root of 2-x}-(x+30)/(3(2-x)^{2/3)

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Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

(x + 30)^{'} = 1

Simplify

\frac{\partial}{\partial x} ((x^{2} + y^{2}) e^{y^{2} - x^{2}})

\int 2 - x d x

x \to 3 + lim (4)

\frac{d}{d x} ((3 x^{2} - 2 x)^{2})

What is the ((x+30)\sqrt[3]{2-x})^' ?
The ((x+30)\sqrt[3]{2-x})^' is cube root of 2-x}-(x+30)/(3(2-x)^{2/3)
What is the first ((x+30)\sqrt[3]{2-x})^' ?
The first ((x+30)\sqrt[3]{2-x})^' is cube root of 2-x}-(x+30)/(3(2-x)^{2/3)