What is the derivative of (3x^2-2x^2) ?

The derivative of (3x^2-2x^2) is 2(3x^2-2x)(6x-2)

What is the first derivative of (3x^2-2x^2) ?

The first derivative of (3x^2-2x^2) is 2(3x^2-2x)(6x-2)

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\frac{d}{d x} ((3 x^{2} - 2 x)^{2})

2 (3 x^{2} - 2 x) (6 x - 2)

Solution steps

\frac{d}{d x} ((3 x^{2} - 2 x)^{2})

Apply the chain rule:

2 (3 x^{2} - 2 x) \frac{d}{d x} (3 x^{2} - 2 x)

= 2 (3 x^{2} - 2 x) \frac{d}{d x} (3 x^{2} - 2 x)

\frac{d}{d x} (3 x^{2} - 2 x) = 6 x - 2

= 2 (3 x^{2} - 2 x) (6 x - 2)

x^{2} \frac{d y}{d x} + y = 0

\frac{d}{d x} (sin^{2} (6 x))

\frac{d}{d x} (1 + x - 1)

(x^{3} - 25 x^{2})^{^{'}}

\int arctan (\frac{2 x}{1 - x ^{2}}) d x

What is the derivative of (3x^2-2x^2) ?
The derivative of (3x^2-2x^2) is 2(3x^2-2x)(6x-2)
What is the first derivative of (3x^2-2x^2) ?
The first derivative of (3x^2-2x^2) is 2(3x^2-2x)(6x-2)