What is the first (x^3-25x^2)^' ?

The first (x^3-25x^2)^' is 3x^2-50x

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(x^3-25x^2)^'

(x^{3} - 25 x^{2})^{^{'}}

3 x^{2} - 50 x

Solution steps

(x^{3} - 25 x^{2})^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (x^{3})^{^{'}} - (25 x^{2})^{^{'}}

(x^{3})^{'} = 3 x^{2}

(25 x^{2})^{'} = 50 x

= 3 x^{2} - 50 x

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