What is (\partial)/(\partial x)(1+3x+2y^2) ?

The answer to (\partial)/(\partial x)(1+3x+2y^2) is 3

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(\partial)/(\partial x)(1+3x+2y^2)

\frac{\partial}{\partial x} (1 + 3 x + 2 y^{2})

3

Solution steps

\frac{\partial}{\partial x} (1 + 3 x + 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 0 + 3 + 0

Simplify

= 3

\frac{\partial}{\partial y} (\frac{y}{7 x})

\frac{d}{d x} (\frac{4 e ^{x}}{cos ( x )})

\int_{1}^{4} (x) d x

\frac{d y}{d x} - \frac{y}{x} = 6 x e^{x}

y^{^{''}} + 4 y^{^{'}} + 4 y = t^{- 2} e^{- 2 t}

What is (\partial)/(\partial x)(1+3x+2y^2) ?
The answer to (\partial)/(\partial x)(1+3x+2y^2) is 3