What is (\partial)/(\partial x)(sin(ct+2x)) ?

The answer to (\partial)/(\partial x)(sin(ct+2x)) is cos(ct+2x)*2

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(\partial)/(\partial x)(sin(ct+2x))

\frac{\partial}{\partial x} (sin (c t + 2 x))

cos (c t + 2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (c t + 2 x))

Treat

c, t

as a constant

Apply the chain rule:

cos (c t + 2 x) \frac{\partial}{\partial x} (c t + 2 x)

= cos (c t + 2 x) \frac{\partial}{\partial x} (c t + 2 x)

\frac{\partial}{\partial x} (c t + 2 x) = 2

= cos (c t + 2 x) \cdot 2

\int lo g_{10} (x + 5) d x

\frac{\partial}{\partial x} (8 x^{6} y^{7} + 6 x^{4} y^{8})

\int \frac{x + 3}{x ^{2} + 6 x + 7} d x

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x + 1})

What is (\partial)/(\partial x)(sin(ct+2x)) ?
The answer to (\partial)/(\partial x)(sin(ct+2x)) is cos(ct+2x)*2