What is the derivative of 8x^2-x^3 ?

The derivative of 8x^2-x^3 is 16x-3x^2

What is the first derivative of 8x^2-x^3 ?

The first derivative of 8x^2-x^3 is 16x-3x^2

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\frac{d}{d x} (8 x^{2} - x^{3})

16 x - 3 x^{2}

Solution steps

\frac{d}{d x} (8 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 16 x - 3 x^{2}

\int_{0}^{x} cos (t) d t

\frac{d ^{2} y}{d x ^{2}} = \frac{1}{x} + 2

x \to - 2 lim (\frac{∣ x - 2 ∣}{x - 2})

\frac{\partial}{\partial x} ((x^{3} + y^{3})^{10})

What is the derivative of 8x^2-x^3 ?
The derivative of 8x^2-x^3 is 16x-3x^2
What is the first derivative of 8x^2-x^3 ?
The first derivative of 8x^2-x^3 is 16x-3x^2