What is the derivative of f(x)=2x+(1936)/x ?

The derivative of f(x)=2x+(1936)/x is 2-(1936)/(x^2)

What is the first derivative of f(x)=2x+(1936)/x ?

The first derivative of f(x)=2x+(1936)/x is 2-(1936)/(x^2)

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derivative of

f (x) = 2 x + \frac{1936}{x}

2 - \frac{1936}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x + \frac{1936}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{1936}{x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{1936}{x}) = - \frac{1936}{x ^{2}}

= 2 - \frac{1936}{x ^{2}}

f (x) = 110 x - 16 x^{2}, at x = 4

(x^{2} - x y) d x + x d y = 0

\frac{1}{x + 8}

\frac{d}{d x} (\frac{e ^{x}}{x ^{2} + 7})

What is the derivative of f(x)=2x+(1936)/x ?
The derivative of f(x)=2x+(1936)/x is 2-(1936)/(x^2)
What is the first derivative of f(x)=2x+(1936)/x ?
The first derivative of f(x)=2x+(1936)/x is 2-(1936)/(x^2)