What is the derivative of 1/(x+8) ?

The derivative of 1/(x+8) is -1/((x+8)^2)

What is the first derivative of 1/(x+8) ?

The first derivative of 1/(x+8) is -1/((x+8)^2)

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derivative of

\frac{1}{x + 8}

- \frac{1}{( x + 8 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 8})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 8)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 8 ) ^{2}} \frac{d}{d x} (x + 8)

= - \frac{1}{( x + 8 ) ^{2}} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= - \frac{1}{( x + 8 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 8 ) ^{2}}

\frac{d}{d x} (\frac{e ^{x}}{x ^{2} + 7})

\int_{1}^{\infty} \frac{5}{2 x} d x

2 y y^{^{'}} + 3 - (y^{2} + 3) = 0, y (0) = 6

f (x) = \frac{3}{3 x + 4}

What is the derivative of 1/(x+8) ?
The derivative of 1/(x+8) is -1/((x+8)^2)
What is the first derivative of 1/(x+8) ?
The first derivative of 1/(x+8) is -1/((x+8)^2)