What is the integral from 0 to sqrt(7 of)(x^3)/(\sqrt[3]{1+x^2)} ?

The integral from 0 to sqrt(7 of)(x^3)/(\sqrt[3]{1+x^2)} is 141/20

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integral from 0 to sqrt(7 of)(x^3)/(\sqrt[3]{1+x^2)}

\frac{141}{20}

Decimal Notation

7.05

Solution steps

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{1}^{8} u^{\frac{2}{3}} d u = \frac{93}{5}

= \frac{1}{2} (\frac{93}{5} - \frac{9}{2})

Simplify

\frac{1}{2} (\frac{93}{5} - \frac{9}{2}) : \frac{141}{20}

= \frac{141}{20}

x \to 3 lim (\frac{( - 4 ) ( 0 )}{4})

\frac{x ^{7} + 2}{x ^{7}}

11 - x^{2} (3.2)

\int tan^{4} (6 x) sec^{2} (6 x) d x

\frac{\partial}{\partial y} (y^{2} - 9)

What is the integral from 0 to sqrt(7 of)(x^3)/(\sqrt[3]{1+x^2)} ?
The integral from 0 to sqrt(7 of)(x^3)/(\sqrt[3]{1+x^2)} is 141/20