What is the solution for xy^'+y=-5xy^2,y(1)=7 ?

The solution for xy^'+y=-5xy^2,y(1)=7 is y= 7/(x(35ln(x)+1))

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xy^'+y=-5xy^2,y(1)=7

x y^{^{'}} + y = - 5 x y^{2}, y (1) = 7

y = \frac{7}{x ( 35 ln ( x ) + 1 )}

Solution steps

x y^{'} (x) + y = - 5 x y^{2}

Solve Bernoulli ODE:

y = \frac{7}{x ( 35 ln ( x ) + 1 )}

y = \frac{7}{x ( 35 ln ( x ) + 1 )}

\int arccot (2 y) d y

y^{^{'}} = \frac{x y ^{3}}{16}

\int x^{2} (4 - 2 x^{2}) d x

f (x) = x (x^{3} - x)

\frac{d}{d x} (\frac{6 x - 3}{5 x + 8})

What is the solution for xy^'+y=-5xy^2,y(1)=7 ?
The solution for xy^'+y=-5xy^2,y(1)=7 is y= 7/(x(35ln(x)+1))