What is the derivative of 2x+sqrt(x) ?

The derivative of 2x+sqrt(x) is 2+1/(2sqrt(x))

What is the first derivative of 2x+sqrt(x) ?

The first derivative of 2x+sqrt(x) is 2+1/(2sqrt(x))

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\frac{d}{d x} (2 x + x)

2 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (2 x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (x)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x) = \frac{1}{2 x}

= 2 + \frac{1}{2 x}

\frac{d}{d x} (x^{4} - 4 x^{2})

\frac{d y}{d t} + e^{t} y = 9 e^{t}

\frac{d y}{d x} = 6 y^{2} x

y = x^{2} - 5 x + 3, (2, - 3)

n = 5 \sum \infty 3 (0.9)^{n + 1}

What is the derivative of 2x+sqrt(x) ?
The derivative of 2x+sqrt(x) is 2+1/(2sqrt(x))
What is the first derivative of 2x+sqrt(x) ?
The first derivative of 2x+sqrt(x) is 2+1/(2sqrt(x))