What is the integral of 1/(sin^2(x)\sqrt[4]{cot(x))} ?

The integral of 1/(sin^2(x)\sqrt[4]{cot(x))} is -4/3 cot^{3/4}(x)+C

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integral of 1/(sin^2(x)\sqrt[4]{cot(x))}

- \frac{4}{3} cot^{\frac{3}{4}} (x) + C

Solution steps

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{4}{3} u^{\frac{3}{4}}

= - \frac{4}{3} u^{\frac{3}{4}}

Substitute back

u = cot (x)

= - \frac{4}{3} cot^{\frac{3}{4}} (x)

Add a constant to the solution

= - \frac{4}{3} cot^{\frac{3}{4}} (x) + C

\int 1 + x^{2} \cdot x^{5} d x

y = - x^{3} + 2 x^{2} - 4, at x = - 1

- sec^{2} (x)

\frac{d}{d n} (e^{niπ})

y^{^{''}} + y^{^{'}} + y = 0

What is the integral of 1/(sin^2(x)\sqrt[4]{cot(x))} ?
The integral of 1/(sin^2(x)\sqrt[4]{cot(x))} is -4/3 cot^{3/4}(x)+C