What is the derivative of f(θ)=θcos(θ) ?

The derivative of f(θ)=θcos(θ) is cos(θ)-θsin(θ)

What is the first derivative of f(θ)=θcos(θ) ?

The first derivative of f(θ)=θcos(θ) is cos(θ)-θsin(θ)

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derivative of

f (θ) = θ cos (θ)

cos (θ) - θ sin (θ)

Solution steps

\frac{d}{d θ} (θ cos (θ))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = θ, g = cos (θ)

= \frac{d}{d θ} (θ) cos (θ) + \frac{d}{d θ} (cos (θ)) θ

\frac{d}{d θ} (θ) = 1

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= 1 \cdot cos (θ) + (- sin (θ)) θ

Simplify

= cos (θ) - θ sin (θ)

n = 2 \sum \infty \frac{1}{n ^{2}}

y = x^{- 4}

\int x^{3} - 5 x d x

e^{x y} + y = x - 1

\frac{x}{x ^{2} + 4}

What is the derivative of f(θ)=θcos(θ) ?
The derivative of f(θ)=θcos(θ) is cos(θ)-θsin(θ)
What is the first derivative of f(θ)=θcos(θ) ?
The first derivative of f(θ)=θcos(θ) is cos(θ)-θsin(θ)