What is the derivative of y=2xe^{-x} ?

The derivative of y=2xe^{-x} is 2(e^{-x}-e^{-x}x)

What is the first derivative of y=2xe^{-x} ?

The first derivative of y=2xe^{-x} is 2(e^{-x}-e^{-x}x)

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derivative of

y = 2 x e^{- x}

2 (e^{- x} - e^{- x} x)

Solution steps

\frac{d}{d x} (2 x e^{- x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x e^{- x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- x}

= 2 (\frac{d x}{d x} e^{- x} + \frac{d}{d x} (e^{- x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 2 (1 \cdot e^{- x} + (- e^{- x}) x)

Simplify

= 2 (e^{- x} - e^{- x} x)

x \to \infty lim (2.5)

\int_{0}^{4} e^{- 2 x} + 4 d x

\int 1 + e^{x} d x

\frac{d y}{d x} = \frac{( y - 3 x ^{2} + y ^{2} )}{x}

x \to 0 lim (x (cos (x)))

What is the derivative of y=2xe^{-x} ?
The derivative of y=2xe^{-x} is 2(e^{-x}-e^{-x}x)
What is the first derivative of y=2xe^{-x} ?
The first derivative of y=2xe^{-x} is 2(e^{-x}-e^{-x}x)