What is the solution for (dy}{dx}=\frac{(y-3sqrt(x^2+y^2)))/x ?

The solution for (dy}{dx}=\frac{(y-3sqrt(x^2+y^2)))/x is y=-(x^4)/(2e^{c_{1)}}+(e^{c_{1}})/(2x^2)

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(dy}{dx}=\frac{(y-3sqrt(x^2+y^2)))/x

\frac{d y}{d x} = \frac{( y - 3 x ^{2} + y ^{2} )}{x}

y = - \frac{x ^{4}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2 x ^{2}}

Solution steps

\frac{d y}{d x} = \frac{( y - 3 x ^{2} + y ^{2} )}{x}

Solve using substitution:

y = - \frac{x ^{4}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2 x ^{2}}

y = - \frac{x ^{4}}{2 e ^{c_{1}}} + \frac{e ^{c_{1}}}{2 x ^{2}}

x \to 0 lim (x (cos (x)))

x \to 0 lim (\frac{3 - 3 cos ( x )}{x})

\frac{d}{d x} (e^{e^{3 x^{2}}})

\frac{d}{d x} (\frac{3}{( x - 2 ) ^{2}})

\frac{d}{d x} (\frac{7}{sin ( x ) + cos ( x )})

What is the solution for (dy}{dx}=\frac{(y-3sqrt(x^2+y^2)))/x ?
The solution for (dy}{dx}=\frac{(y-3sqrt(x^2+y^2)))/x is y=-(x^4)/(2e^{c_{1)}}+(e^{c_{1}})/(2x^2)