What is the derivative of 3/((x-2^2)) ?

The derivative of 3/((x-2^2)) is -6/((x-2)^3)

What is the first derivative of 3/((x-2^2)) ?

The first derivative of 3/((x-2^2)) is -6/((x-2)^3)

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\frac{d}{d x} (\frac{3}{( x - 2 ) ^{2}})

- \frac{6}{( x - 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{3}{( x - 2 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{( x - 2 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x - 2)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 2 ) ^{3}} \frac{d}{d x} (x - 2)

= - \frac{2}{( x - 2 ) ^{3}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 3 (- \frac{2}{( x - 2 ) ^{3}} \cdot 1)

Simplify

3 (- \frac{2}{( x - 2 ) ^{3}} \cdot 1) : - \frac{6}{( x - 2 ) ^{3}}

= - \frac{6}{( x - 2 ) ^{3}}

\frac{d}{d x} (\frac{7}{sin ( x ) + cos ( x )})

\int \frac{- cos ( 4 t ) sin ( 4 t )}{4} d t

\int sin^{4} (x) cos^{7} (x) d x

\int 4 x - 11 d x

y^{^{'}} = e^{4 c o s (x)}

What is the derivative of 3/((x-2^2)) ?
The derivative of 3/((x-2^2)) is -6/((x-2)^3)
What is the first derivative of 3/((x-2^2)) ?
The first derivative of 3/((x-2^2)) is -6/((x-2)^3)