What is the derivative of y=sqrt(x+7) ?

The derivative of y=sqrt(x+7) is 1/(2sqrt(x+7))

What is the first derivative of y=sqrt(x+7) ?

The first derivative of y=sqrt(x+7) is 1/(2sqrt(x+7))

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derivative of

y = x + 7

\frac{1}{2 x + 7}

Solution steps

\frac{d}{d x} (x + 7)

Apply the chain rule:

\frac{1}{2 x + 7} \frac{d}{d x} (x + 7)

= \frac{1}{2 x + 7} \frac{d}{d x} (x + 7)

\frac{d}{d x} (x + 7) = 1

= \frac{1}{2 x + 7} \cdot 1

Simplify

= \frac{1}{2 x + 7}

\frac{d y}{d x} = (1 + 4 y^{2}) (1 + 3 x^{2})

x \to 0 lim (\frac{sin ( 7 x )}{sin ( 9 x )})

\int 1 - tan^{2} (x) d x

(x^{3} + 4) e^{x}

f (x) = (1 - x) (x^{2} - 3) 2

What is the derivative of y=sqrt(x+7) ?
The derivative of y=sqrt(x+7) is 1/(2sqrt(x+7))
What is the first derivative of y=sqrt(x+7) ?
The first derivative of y=sqrt(x+7) is 1/(2sqrt(x+7))