What is the derivative of (8x+5^2) ?

The derivative of (8x+5^2) is 16(8x+5)

What is the first derivative of (8x+5^2) ?

The first derivative of (8x+5^2) is 16(8x+5)

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\frac{d}{d x} ((8 x + 5)^{2})

16 (8 x + 5)

Solution steps

\frac{d}{d x} ((8 x + 5)^{2})

Apply the chain rule:

2 (8 x + 5) \frac{d}{d x} (8 x + 5)

= 2 (8 x + 5) \frac{d}{d x} (8 x + 5)

\frac{d}{d x} (8 x + 5) = 8

= 2 (8 x + 5) \cdot 8

Simplify

= 16 (8 x + 5)

y = 5 x - 2 x^{2}, (- 2, - 18)

\frac{d}{d x} (\frac{x + 7}{x - 7})

y = 3 x + 72, (3, 9)

y = \frac{7 x}{8}

x \to 0 lim (\frac{x ^{2}}{e ^{x} - 1})

What is the derivative of (8x+5^2) ?
The derivative of (8x+5^2) is 16(8x+5)
What is the first derivative of (8x+5^2) ?
The first derivative of (8x+5^2) is 16(8x+5)