What is (\partial)/(\partial x)(ye^x-x^2y^{-3}) ?

The answer to (\partial)/(\partial x)(ye^x-x^2y^{-3}) is ye^x-(2x)/(y^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(ye^x-x^2y^{-3})

\frac{\partial}{\partial x} (y e^{x} - x^{2} y^{- 3})

y e^{x} - \frac{2 x}{y ^{3}}

Solution steps

\frac{\partial}{\partial x} (y e^{x} - x^{2} y^{- 3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y e^{x}) - \frac{\partial}{\partial x} (x^{2} y^{- 3})

\frac{\partial}{\partial x} (y e^{x}) = y e^{x}

\frac{\partial}{\partial x} (x^{2} y^{- 3}) = \frac{2 x}{y ^{3}}

= y e^{x} - \frac{2 x}{y ^{3}}

y = \frac{4 x}{x ^{2} + 1}, (0, 0)

x \to - 1 lim (x^{2} - 2 x + 3)

\frac{d}{d x} (- \frac{cos ^{4} ( x )}{4})

\int 1 - e^{- 2 x} d x

sin (x) sec (y) d x = d y

What is (\partial)/(\partial x)(ye^x-x^2y^{-3}) ?
The answer to (\partial)/(\partial x)(ye^x-x^2y^{-3}) is ye^x-(2x)/(y^3)