What is the tangent of y=(4x)/(x^2+1),(0,0) ?

The tangent of y=(4x)/(x^2+1),(0,0) is y=4x

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tangent of y=(4x)/(x^2+1),(0,0)

tangent of

y = \frac{4 x}{x ^{2} + 1}, (0, 0)

y = 4 x

Solution steps

Find the slope of

y = \frac{4 x}{x ^{2} + 1} : \frac{d y}{d x} = \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x ^{2} + 1}

(0, 0) : m = 4

Find the line with slope m=

4

and passing through

(0, 0) : y = 4 x

y = 4 x

x \to - 1 lim (x^{2} - 2 x + 3)

\frac{d}{d x} (- \frac{cos ^{4} ( x )}{4})

\int 1 - e^{- 2 x} d x

sin (x) sec (y) d x = d y

\int \frac{- 1}{1 - x ^{2}} d x

What is the tangent of y=(4x)/(x^2+1),(0,0) ?
The tangent of y=(4x)/(x^2+1),(0,0) is y=4x