What is (\partial)/(\partial y)(2x^2y^2) ?

The answer to (\partial)/(\partial y)(2x^2y^2) is 4x^2y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2x^2y^2)

\frac{\partial}{\partial y} (2 x^{2} y^{2})

4 x^{2} y

Solution steps

\frac{\partial}{\partial y} (2 x^{2} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{2} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2} \cdot 2 y^{2 - 1}

Simplify

= 4 x^{2} y

t \to - \infty lim (- \frac{1}{3} + \frac{1}{3} e^{- t^{3}})

y^{^{''}} - 9 y^{^{'}} + 9 y = 0

n = 1 \sum \infty \frac{2}{n + 7}

y = 6 x, y = 2 x^{2}

What is (\partial)/(\partial y)(2x^2y^2) ?
The answer to (\partial)/(\partial y)(2x^2y^2) is 4x^2y