What is (\partial)/(\partial x)(-2ysin(x)) ?

The answer to (\partial)/(\partial x)(-2ysin(x)) is -2ycos(x)

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(\partial)/(\partial x)(-2ysin(x))

\frac{\partial}{\partial x} (- 2 y sin (x))

- 2 y cos (x)

Solution steps

\frac{\partial}{\partial x} (- 2 y sin (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 y \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - 2 y cos (x)

y^{^{''}} + 4 y = e^{- t}

7 (4 e^{x} - 27)^{5}

\int_{1}^{5} 1 + 2^{2} d x

x \to \infty lim (\frac{1}{9})

7^{^{'}}

What is (\partial)/(\partial x)(-2ysin(x)) ?
The answer to (\partial)/(\partial x)(-2ysin(x)) is -2ycos(x)