What is the solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=3 ?

The solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=3 is y=4e^{-1/t+1}t-1

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t^2(dy)/(dt)-t=1+y+ty,y(1)=3

t^{2} \frac{d y}{d t} - t = 1 + y + t y, y (1) = 3

y = 4 e^{- \frac{1}{t} + 1} t - 1

Solution steps

t^{2} \frac{d y}{d t} - t = 1 + y + t y

Solve separable ODE:

y = 4 e^{- \frac{1}{t} + 1} t - 1

y = 4 e^{- \frac{1}{t} + 1} t - 1

\frac{\partial}{\partial x} (2 (x - y) e^{2 y + x^{2}})

\int 8 x cos^{2} (x) d x

\frac{\partial}{\partial x} ((x - 7)^{2} + (y - 1)^{2} + 29)

x \to 4 lim (\frac{3}{x - 4})

n \to \infty lim (i = 3 \sum 8 (i + 1)^{2})

What is the solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=3 ?
The solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=3 is y=4e^{-1/t+1}t-1