What is the integral from t+2 to t+4 of 3 ?

The integral from t+2 to t+4 of 3 is 6

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integral from t+2 to t+4 of 3

\int_{t + 2}^{t + 4} 3 d x

6

Solution steps

\int_{t + 2}^{t + 4} 3 d x

Integral of a constant:

\int a d x = a x

= [3 x]_{t + 2}^{t + 4}

Compute the boundaries:

6

= 6

y = (4 x + 1)^{2}, (0, 1)

f (- 8) = 6 (1 - x)

x \to 1 - lim (\frac{x - 2}{x - 1})

\frac{d}{d x} (ln (\frac{x - 1}{x + 2}))

\int_{- 3}^{5} 4 d x

What is the integral from t+2 to t+4 of 3 ?
The integral from t+2 to t+4 of 3 is 6