What is the solution for y'=0.0013y(3000-y) ?

The solution for y'=0.0013y(3000-y) is y=(3.9)/(-e^{-3.89999…t-c_{1)}+0.0013}

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y'=0.0013y(3000-y)

y^{^{'}} = 0.0013 y (3000 - y)

y = \frac{3.9}{- e ^{- 3.89999 \dots t - c_{1}} + 0.0013}

Solution steps

y^{'} (t) = 0.0013 y (3000 - y)

Solve Bernoulli ODE:

y = \frac{3.9}{- e ^{- 3.89999 \dots t - c_{1}} + 0.0013}

y = \frac{3.9}{- e ^{- 3.89999 \dots t - c_{1}} + 0.0013}

y = 3 x^{3} - x^{2} + 7, (2, 27)

\int (x + 4) (x + 2) d x

\int (4 x^{2}) d x

y = 13 x, y = x^{2}

\int \frac{( 2 + x + x )}{x} d x

What is the solution for y'=0.0013y(3000-y) ?
The solution for y'=0.0013y(3000-y) is y=(3.9)/(-e^{-3.89999…t-c_{1)}+0.0013}