What is the tangent of f(x)=sqrt(5x+6),\at x=6 ?

The tangent of f(x)=sqrt(5x+6),\at x=6 is y= 5/12 x+7/2

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tangent of f(x)=sqrt(5x+6),\at x=6

tangent of

f (x) = 5 x + 6, at x = 6

y = \frac{5}{12} x + \frac{7}{2}

Solution steps

Find the tangent point:

(6, 6)

Find the slope of

f (x) = 5 x + 6 : \frac{df ( x )}{d x} = \frac{5}{2 5 x + 6}

Compute the slope of

f (x) = 5 x + 6

x = 6 : m = \frac{5}{12}

Find the line with slope m=

\frac{5}{12}

and passing through

(6, 6) : y = \frac{5}{12} x + \frac{7}{2}

y = \frac{5}{12} x + \frac{7}{2}

5 \cdot \frac{d Q}{d t} + \frac{Q}{3} = 0

f (x) = 5 e^{x}

x^{2} \frac{d y}{d x} + x y = x^{3}

- x^{2} + 4 x, at x = 4

\int x + y + 1 d x

What is the tangent of f(x)=sqrt(5x+6),\at x=6 ?
The tangent of f(x)=sqrt(5x+6),\at x=6 is y= 5/12 x+7/2