What is the derivative of cos(2^x) ?

The derivative of cos(2^x) is -sin(2^x)*2^xln(2)

What is the first derivative of cos(2^x) ?

The first derivative of cos(2^x) is -sin(2^x)*2^xln(2)

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derivative of

cos (2^{x})

- sin (2^{x}) \cdot 2^{x} ln (2)

Solution steps

\frac{d}{d x} (cos (2^{x}))

Apply the chain rule:

- sin (2^{x}) \frac{d}{d x} (2^{x})

= - sin (2^{x}) \frac{d}{d x} (2^{x})

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

= - sin (2^{x}) \cdot 2^{x} ln (2)

(- 19 x y^{2} + 10 y) + (- 19 x^{2} y + 10 x) y^{^{'}} = 0

x^{2} y \frac{d y}{d x} = e^{y}

x \to 2 - lim (\frac{x - 2}{∣ x - 2 ∣})

y^{^{'}} = \frac{( 3 x ^{2} - e ^{x} )}{2 y - 5}

y^{^{''}} + 11 y^{^{'}} + 30 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the derivative of cos(2^x) ?
The derivative of cos(2^x) is -sin(2^x)*2^xln(2)
What is the first derivative of cos(2^x) ?
The first derivative of cos(2^x) is -sin(2^x)*2^xln(2)