What is the derivative of 2xy+x^2-1 ?

The derivative of 2xy+x^2-1 is 2x+2(x(dy)/(dx)+y)

What is the first derivative of 2xy+x^2-1 ?

The first derivative of 2xy+x^2-1 is 2x+2(x(dy)/(dx)+y)

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\frac{d}{d x} (2 x y + x^{2} - 1)

2 x + 2 (x \frac{d y}{d x} + y)

Solution steps

\frac{d}{d x} (2 x y + x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x y) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x y) = 2 (y + x \frac{d y}{d x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 (y + x \frac{d y}{d x}) + 2 x - 0

Simplify

= 2 x + 2 (x \frac{d y}{d x} + y)

\frac{( x ^{4} + 1 )}{e ^{x} + 2 x + 1}

12 x^{3} - 24 x^{2}

f (I) = I^{22}

\int \frac{x ^{2} + 8}{x ^{4} - x ^{3} - 2 x ^{2}} d x

x \to + x lim (\frac{x ^{2} - 1}{x - 1})

What is the derivative of 2xy+x^2-1 ?
The derivative of 2xy+x^2-1 is 2x+2(x(dy)/(dx)+y)
What is the first derivative of 2xy+x^2-1 ?
The first derivative of 2xy+x^2-1 is 2x+2(x(dy)/(dx)+y)