What is the tangent of e^{x^7} ?

The tangent of e^{x^7} is y=e^{a_{0}^7}*7a_{0}^6x+e^{a_{0}^7}-7a_{0}^7e^{a_{0}^7}

Popular >

tangent of e^{x^7}

tangent of

e^{x^{7}}

y = e^{a_{0}^{7}} \cdot 7 a_{0}^{6} x + e^{a_{0}^{7}} - 7 a_{0}^{7} e^{a_{0}^{7}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, e^{a_{0}^{7}})

Find the slope of

y = e^{x^{7}} : \frac{d y}{d x} = e^{x^{7}} \cdot 7 x^{6}

Compute the slope of

y = e^{x^{7}}

x = a_{0} : m = e^{a_{0}^{7}} \cdot 7 a_{0}^{6}

Find the line with slope m=

e^{a_{0}^{7}} 7 a_{0}^{6}

and passing through

(a_{0}, e^{a_{0}^{7}}) : y = e^{a_{0}^{7}} \cdot 7 a_{0}^{6} x + e^{a_{0}^{7}} - 7 a_{0}^{7} e^{a_{0}^{7}}

y = e^{a_{0}^{7}} \cdot 7 a_{0}^{6} x + e^{a_{0}^{7}} - 7 a_{0}^{7} e^{a_{0}^{7}}

x^{2} y^{^{''}} + x y^{^{'}} + 4 = 0

y^{^{''}} + 7 y^{^{'}} - 3 y = 0, y (0) = - 3, y^{^{'}} (0) = 7

\int \frac{2 x ^{\frac{3}{2}}}{3} d x

\frac{d y}{d x} = \frac{x ^{2} y ^{2}}{1 + y}

x \to 2 - lim (4 x - 5)

What is the tangent of e^{x^7} ?
The tangent of e^{x^7} is y=e^{a_{0}^7}*7a_{0}^6x+e^{a_{0}^7}-7a_{0}^7e^{a_{0}^7}