What is laplacetransform sin(2x+3) ?

The answer to laplacetransform sin(2x+3) is (sin(3)s+2cos(3))/(s^2+4)

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laplacetransform sin(2x+3)

laplace transform

sin (2 x + 3)

\frac{sin ( 3 ) s + 2 cos ( 3 )}{s ^{2} + 4}

Solution steps

L {sin (2 x + 3)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (2 x + 3)} = \frac{s sin ( 3 ) + 2 cos ( 3 )}{s ^{2} + 2 ^{2}}

= \frac{s sin ( 3 ) + 2 cos ( 3 )}{s ^{2} + 2 ^{2}}

= \frac{sin ( 3 ) s + 2 cos ( 3 )}{s ^{2} + 4}

x \to 0 lim (x^{3} cos (\frac{5}{x}))

\frac{\partial}{\partial y} (\frac{x}{y + 1})

y = 3 x^{2}, y = 2 - x, x = 0

\int \frac{4}{3 x} d x

y = ln (x^{2} + 3)

What is laplacetransform sin(2x+3) ?
The answer to laplacetransform sin(2x+3) is (sin(3)s+2cos(3))/(s^2+4)