What is the integral of x^2e^{-x^2} ?

The integral of x^2e^{-x^2} is -1/2 e^{-x^2}x+(sqrt(pi))/4 \erf(x)+C

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integral of x^2e^{-x^2}

\int x^{2} e^{- x^{2}} d x

- \frac{1}{2} e^{- x^{2}} x + \frac{π}{4} erf (x) + C

Solution steps

\int x^{2} e^{- x^{2}} d x

Simplify

x^{2} : xx

= \int xx e^{- x^{2}} d x

Apply Integration By Parts

: - \frac{1}{2} e^{- x^{2}} x - \int - \frac{1}{2} e^{- x^{2}} d x

= - \frac{1}{2} e^{- x^{2}} x - \int - \frac{1}{2} e^{- x^{2}} d x

\int - \frac{1}{2} e^{- x^{2}} d x = - \frac{π}{4} erf (x)

= - \frac{1}{2} e^{- x^{2}} x - (- \frac{π}{4} erf (x))

Simplify

= - \frac{1}{2} e^{- x^{2}} x + \frac{π}{4} erf (x)

Add a constant to the solution

= - \frac{1}{2} e^{- x^{2}} x + \frac{π}{4} erf (x) + C

\int (4 x^{3} - 3 x^{2} + 2 x - 5) d x

\frac{d}{d x} (f (\frac{1}{3} x^{3})) = 2 x^{5}

\frac{d}{d x} (2 cos (x) + (cos (x))^{2})

y^{^{'}} = \frac{y ^{4} x ^{4} + 4 x ^{4}}{y ^{3}}

\int \frac{x + 7}{x ^{2} ( x + 2 )} d x

What is the integral of x^2e^{-x^2} ?
The integral of x^2e^{-x^2} is -1/2 e^{-x^2}x+(sqrt(pi))/4 \erf(x)+C