What is the derivative of (1/2 ^x) ?

The derivative of (1/2 ^x) is -ln(2)(1/2)^x

What is the first derivative of (1/2 ^x) ?

The first derivative of (1/2 ^x) is -ln(2)(1/2)^x

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\frac{d}{d x} ((\frac{1}{2})^{x})

- ln (2) (\frac{1}{2})^{x}

Solution steps

\frac{d}{d x} ((\frac{1}{2})^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= (\frac{1}{2})^{x} ln (\frac{1}{2})

Simplify

(\frac{1}{2})^{x} ln (\frac{1}{2}) : - ln (2) (\frac{1}{2})^{x}

= - ln (2) (\frac{1}{2})^{x}

y^{^{''}} - 9 y^{^{'}} + 3 y = x e^{x}

\int (x^{3} + x^{2} + 2 x - 3) d x

\frac{d}{d x} ((a x^{2} + b x + c) e^{- \frac{x}{6}})

y = 7 sin (4 x)

\frac{\partial}{\partial y} (x^{2} y^{5})

What is the derivative of (1/2 ^x) ?
The derivative of (1/2 ^x) is -ln(2)(1/2)^x
What is the first derivative of (1/2 ^x) ?
The first derivative of (1/2 ^x) is -ln(2)(1/2)^x