What is the derivative of 3/(1-6x) ?

The derivative of 3/(1-6x) is (18)/((1-6x)^2)

What is the first derivative of 3/(1-6x) ?

The first derivative of 3/(1-6x) is (18)/((1-6x)^2)

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derivative of

\frac{3}{1 - 6 x}

\frac{18}{( 1 - 6 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{1 - 6 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{1 - 6 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((1 - 6 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 6 x ) ^{2}} \frac{d}{d x} (1 - 6 x)

= - \frac{1}{( 1 - 6 x ) ^{2}} \frac{d}{d x} (1 - 6 x)

\frac{d}{d x} (1 - 6 x) = - 6

= 3 (- \frac{1}{( 1 - 6 x ) ^{2}} (- 6))

Simplify

3 (- \frac{1}{( 1 - 6 x ) ^{2}} (- 6)) : \frac{18}{( 1 - 6 x ) ^{2}}

= \frac{18}{( 1 - 6 x ) ^{2}}

y^{^{'}} = e^{- 3 x}

x \to 5 lim (\frac{∣ x - 5 ∣}{x - 5})

\int_{1}^{5} x^{2} ln (x) d x

\frac{d y}{d x} = \frac{1}{5} (8 - y)

1 - \frac{1}{1 + x}

What is the derivative of 3/(1-6x) ?
The derivative of 3/(1-6x) is (18)/((1-6x)^2)
What is the first derivative of 3/(1-6x) ?
The first derivative of 3/(1-6x) is (18)/((1-6x)^2)