What is the solution for 2(ln(y))y^'-x^5y=0 ?

The solution for 2(ln(y))y^'-x^5y=0 is y=e^{sqrt((x^6+c_{1))/6}},y=e^{-sqrt((x^6+c_{1))/6}}

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2(ln(y))y^'-x^5y=0

2 (ln (y)) y^{^{'}} - x^{5} y = 0

y = e^{\frac{x ^{6} + c _{1}}{6}}, y = e^{- \frac{x ^{6} + c _{1}}{6}}

Solution steps

2 (ln (y)) y^{'} (x) - x^{5} y = 0

Solve separable ODE:

y = e^{\frac{x ^{6} + c _{1}}{6}}, y = e^{- \frac{x ^{6} + c _{1}}{6}}

y = e^{\frac{x ^{6} + c _{1}}{6}}, y = e^{- \frac{x ^{6} + c _{1}}{6}}

y = cos (a^{5} + x^{5})

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What is the solution for 2(ln(y))y^'-x^5y=0 ?
The solution for 2(ln(y))y^'-x^5y=0 is y=e^{sqrt((x^6+c_{1))/6}},y=e^{-sqrt((x^6+c_{1))/6}}