What is the solution for (dy)/(dt)=((y+2))/(2t+1) ?

The solution for (dy)/(dt)=((y+2))/(2t+1) is y=c_{1}sqrt(2t+1)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=((y+2))/(2t+1)

\frac{d y}{d t} = \frac{( y + 2 )}{2 t + 1}

y = c_{1} 2 t + 1 - 2

Solution steps

\frac{d y}{d t} = \frac{( y + 2 )}{2 t + 1}

Solve separable ODE:

y = c_{1} 2 t + 1 - 2

y = c_{1} 2 t + 1 - 2

\frac{\partial}{\partial v} (3 cos (u))

- 16 (x^{- 6} - x^{12})

\frac{d}{d x} (\frac{x e ^{x}}{x ^{2} + 1})

\frac{d v}{d t} = \frac{( - 5 v - 29.4 )}{3}

\frac{d}{d x} (x^{- 3} ln (x))

What is the solution for (dy)/(dt)=((y+2))/(2t+1) ?
The solution for (dy)/(dt)=((y+2))/(2t+1) is y=c_{1}sqrt(2t+1)-2