What is the solution for (dv}{dt}=\frac{(-5v-29.4))/3 ?

The solution for (dv}{dt}=\frac{(-5v-29.4))/3 is v=-0.2e^{(-5t-c_{1})/3}-5.88

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dv}{dt}=\frac{(-5v-29.4))/3

\frac{d v}{d t} = \frac{( - 5 v - 29.4 )}{3}

v = - 0.2 e^{\frac{- 5 t - c _{1}}{3}} - 5.88

Solution steps

\frac{d v}{d t} = \frac{( - 5 v - 29.4 )}{3}

Solve separable ODE:

v = - 0.2 e^{\frac{- 5 t - c _{1}}{3}} - 5.88

v = - 0.2 e^{\frac{- 5 t - c _{1}}{3}} - 5.88

\frac{d}{d x} (x^{- 3} ln (x))

\int_{0}^{3} 2 x d x

x \to \frac{1}{2} π lim (tan (x))

t \frac{d y}{d t} = t^{3} + 19 t^{3} y

s^{2}

What is the solution for (dv}{dt}=\frac{(-5v-29.4))/3 ?
The solution for (dv}{dt}=\frac{(-5v-29.4))/3 is v=-0.2e^{(-5t-c_{1})/3}-5.88