What is the derivative of 2x+ln(x) ?

The derivative of 2x+ln(x) is 2+1/x

What is the first derivative of 2x+ln(x) ?

The first derivative of 2x+ln(x) is 2+1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x + ln (x))

2 + \frac{1}{x}

Solution steps

\frac{d}{d x} (2 x + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 + \frac{1}{x}

y = \frac{1}{1 - x}

\frac{x ^{2} + 5}{x}

x \to 4 lim (lo g_{2} (x))

\frac{\partial}{\partial x} (x^{2} + 2 x y - y^{2})

What is the derivative of 2x+ln(x) ?
The derivative of 2x+ln(x) is 2+1/x
What is the first derivative of 2x+ln(x) ?
The first derivative of 2x+ln(x) is 2+1/x