What is the integral of-3/(sqrt(x)) ?

The integral of-3/(sqrt(x)) is -6sqrt(x)+C

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integral of-3/(sqrt(x))

\int - \frac{3}{x} d x

- 6 x + C

Solution steps

\int - \frac{3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= - 3 \cdot 2 x^{\frac{1}{2}}

Simplify

- 3 \cdot 2 x^{\frac{1}{2}} : - 6 x

= - 6 x

Add a constant to the solution

= - 6 x + C

f (x) = (x - 1) (x^{2} + 2)^{3}

\int sin (x) cos (x) d x

\frac{\partial}{\partial y} (e^{x} \cdot cos (y))

ln (2 x), 1

\frac{\partial}{\partial x} (e^{x} cos (θ))

What is the integral of-3/(sqrt(x)) ?
The integral of-3/(sqrt(x)) is -6sqrt(x)+C