What is the integral from 115 to 150 of (75)/(2x^2) ?

The integral from 115 to 150 of (75)/(2x^2) is 7/92

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integral from 115 to 150 of (75)/(2x^2)

\int_{115}^{150} \frac{75}{2 x ^{2}} d x

\frac{7}{92}

Decimal Notation

0.07608 \dots

Solution steps

\int_{115}^{150} \frac{75}{2 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{75}{2} \cdot \int_{115}^{150} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{115}^{150}

= \frac{75}{2} [- \frac{1}{x}]_{115}^{150}

Compute the boundaries:

\frac{7}{3450}

= \frac{75}{2} \cdot \frac{7}{3450}

Simplify

= \frac{7}{92}

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\int \frac{1}{16 - x ^{2}} d x

\int 4 x d x

What is the integral from 115 to 150 of (75)/(2x^2) ?
The integral from 115 to 150 of (75)/(2x^2) is 7/92