What is the integral from x to 1/2 of 8 ?

The integral from x to 1/2 of 8 is 4-8x

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integral from x to 1/2 of 8

\int_{x}^{\frac{1}{2}} 8 d y

4 - 8 x

Solution steps

\int_{x}^{\frac{1}{2}} 8 d y

Integral of a constant:

\int a d x = a x

= [8 y]_{x}^{\frac{1}{2}}

Compute the boundaries:

4 - 8 x

= 4 - 8 x

(2 x - 1) d x + (7 y + 3) d y = 0

\frac{d}{d x} (2 x cos (2 x) - (x - 2)^{2})

x \to - 2 lim (x^{2} + 4 x + 4)

\frac{d}{d x} (\frac{2 arctan ( x )}{x ^{2} + 1})

f (x) = 2 x^{4} - x^{3} + 6 x^{2}

What is the integral from x to 1/2 of 8 ?
The integral from x to 1/2 of 8 is 4-8x