What is the derivative of 2xcos(2x-(x-2)^2) ?

The derivative of 2xcos(2x-(x-2)^2) is -2x+2(-2xsin(2x)+cos(2x))+4

What is the first derivative of 2xcos(2x-(x-2)^2) ?

The first derivative of 2xcos(2x-(x-2)^2) is -2x+2(-2xsin(2x)+cos(2x))+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x cos (2 x) - (x - 2)^{2})

- 2 x + 2 (- 2 x sin (2 x) + cos (2 x)) + 4

Solution steps

\frac{d}{d x} (2 x cos (2 x) - (x - 2)^{2})

Simplify

2 x cos (2 x) - (x - 2)^{2} : 2 x cos (2 x) - x^{2} + 4 x - 4

= \frac{d}{d x} (2 x cos (2 x) - x^{2} + 4 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x cos (2 x)) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x cos (2 x)) = 2 (cos (2 x) - 2 x sin (2 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (4) = 0

= 2 (cos (2 x) - 2 x sin (2 x)) - 2 x + 4 - 0

Simplify

= - 2 x + 2 (- 2 x sin (2 x) + cos (2 x)) + 4

x \to - 2 lim (x^{2} + 4 x + 4)

\frac{d}{d x} (\frac{2 arctan ( x )}{x ^{2} + 1})

f (x) = 2 x^{4} - x^{3} + 6 x^{2}

\frac{x ^{2}}{x - 2}

\int tan (m x) sec^{2} (m x) d x

What is the derivative of 2xcos(2x-(x-2)^2) ?
The derivative of 2xcos(2x-(x-2)^2) is -2x+2(-2xsin(2x)+cos(2x))+4
What is the first derivative of 2xcos(2x-(x-2)^2) ?
The first derivative of 2xcos(2x-(x-2)^2) is -2x+2(-2xsin(2x)+cos(2x))+4