What is the integral of cos(x)\sqrt[3]{2018+sin(x)} ?

The integral of cos(x)\sqrt[3]{2018+sin(x)} is 3/4 (2018+sin(x))^{4/3}+C

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integral of cos(x)\sqrt[3]{2018+sin(x)}

\frac{3}{4} (2018 + sin (x))^{\frac{4}{3}} + C

Solution steps

Apply u-substitution

Apply the Power Rule

: \frac{3}{4} v^{\frac{4}{3}}

= \frac{3}{4} v^{\frac{4}{3}}

Substitute back

= \frac{3}{4} (2018 + sin (x))^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} (2018 + sin (x))^{\frac{4}{3}} + C

\frac{\partial}{\partial x} (x^{0.5} y^{0.5})

\frac{\partial}{\partial x} (sin (- 6 x - 3 y))

y = 3 x + 5

n = 0 \sum \infty \frac{n}{8 ^{n}}

\int 14 x^{\frac{1}{3}} d x

What is the integral of cos(x)\sqrt[3]{2018+sin(x)} ?
The integral of cos(x)\sqrt[3]{2018+sin(x)} is 3/4 (2018+sin(x))^{4/3}+C