What is the solution for (dy}{dx}=\frac{x^2+3)/y ?

The solution for (dy}{dx}=\frac{x^2+3)/y is y=sqrt((2x^3)/3+6x+c_{1)},y=-sqrt((2x^3)/3+6x+c_{1)}

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(dy}{dx}=\frac{x^2+3)/y

\frac{d y}{d x} = \frac{x ^{2} + 3}{y}

y = \frac{2 x ^{3}}{3} + 6 x + c_{1}, y = - \frac{2 x ^{3}}{3} + 6 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + 3}{y}

Solve separable ODE:

y = \frac{2 x ^{3}}{3} + 6 x + c_{1}, y = - \frac{2 x ^{3}}{3} + 6 x + c_{1}

y = \frac{2 x ^{3}}{3} + 6 x + c_{1}, y = - \frac{2 x ^{3}}{3} + 6 x + c_{1}

f (x) = ln (x^{2} - 4)

\int (x - 1) e^{- x} d x

\frac{d ^{2}}{d x ^{2}} (6 x + 17)

t \to \infty lim (- e^{- t})

\int sin^{2} (x) \cdot cos^{4} (x) d x

What is the solution for (dy}{dx}=\frac{x^2+3)/y ?
The solution for (dy}{dx}=\frac{x^2+3)/y is y=sqrt((2x^3)/3+6x+c_{1)},y=-sqrt((2x^3)/3+6x+c_{1)}